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Q: If there are 150 nickels and dimes and 70 more are nickels than dimes how many of each are there?

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Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?

7 nickels, 4 dimes, 3 quarters

13 nickels and 78 dime

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7 nickels, 4 dimes, and 3 quarters.

110 nickels and 40 dimes my little brother had the same problem

Eighteen

there r 40 nikels

they were made that way

3 dimes is 30 cents and 5 nickels is 25 cents so 3 dimes is worth more.

You will need at least one nickel. With one nickel you would need 12 dimes to make $1.25. If you have more nickels, then subtract one dime for every two additional nickels you have, so if you have 5 nickels you will need 10 dimes.

You do. 6 dimes = 60 cents 9 nickels = 45 cents 6 dimes = 12 nickels

10(x+5) + 5(x) = 18515x + 50 = 18515x = 135x = 9there are 9 nickels

Jack would have 11 Nickles && 7 Dimes. Promise you thattt, (:

(dimes X 10) + (nickels X 5) = 145 and dimes - nickels = 4 14 dimes + 1 nickel =145 13 dimes + 3 nickel =145 12 dimes + 5 nickel =145 11 dimes + 7 nickel =145 10 dimes + 9 nickel =145 since 11-7 = 4 11 dimes + 7 nickels =145

More than 25.

The question is incomplete. Please post a new version with the rest of the problem.

The dimes.The dimes.The dimes.The dimes.

There are 11 combinations. Beginning with the largest coin, they are:1) 3 quarters, 1 dime, and 2 nickels2) 2 quarters, 4 dimes, 1 nickel3) 2 quarters, 3 dimes, 3 nickels4) 2 quarters, 2 dimes, 5 nickels5) 2 quarters, 1 dime, 7 nickels6) 1 quarter, 6 dimes, 2 nickels7) 1 quarter, 5 dimes, 4 nickels8) 1 quarter, 4 dimes, 6 nickels9) 1 quarter, 3 dimes, 8 nickels10) 1 quarter, 2 dimes, 10 nickels11) 1 quarter, 1 dime, 12 nickelsIf you do not need to use all three coins, there are 15 more combinations:12) 3 quarters, 2 dimes13) 3 quarters, 4 nickels14) 2 quarters, 9 nickels15) 1 quarter, 7 dimes16) 1 quarter, 14 nickels17) 9 dimes, 1 nickel18) 8 dimes, 3 nickels19) 7 dimes, 5 nickels20) 6 dimes, 7 nickels21) 5 dimes, 9 nickels22) 4 dimes, 11 nickels23) 3 dimes, 13 nickels24) 2 dimes, 15 nickels25) 1 dime, 17 nickels26) 19 nickels

d = n + 4; 10d + 5n = 160 so 10 (n +4) + 5n = 160 ie 10n + 40 + 5n + 160 ie 15n = 120 ie n = 8, so d= 12 Check: 12 dimes = $1.20, 8 nickels = 40c, total $1.60

Let D = the number of dimes Let N = the number of nickels 10D + 5N = 170 N = D + 10 10D + 5(D + 10) = 170 10D + 5D + 50 = 170 15D = 120 D = 120/15 D = 8 N = 18

They weigh the same.

65 pennies 0 dimes and 13 nickels 1 dime and 10 nickels 2 dimes and 9 nickels 3 dimes and 7 nickels 4 dimes and 5 nickels 5 dimes and 3 nickels 6 dimes and 1 nickel 2 quarters and 1 dime and 1 nickel That's all I can think of, but there are much more!

The volume of a dime is roughly half the volume of a nickel, so any specific number of dimes would take up about half as much space as the same number of nickels*. In other words, a half a trunk of dimes would have at least the same number of that coin as a full trunk of nickels. However each dime is worth twice as much so the half-trunk of dimes would be worth more. * Because dimes are smaller they'd be able to pack somewhat more tightly than nickels so you could probably get slightly more dimes into the half-trunk. However that doesn't affect the answer; it simply means the half-trunk would be worth even more.